class Solution:
def longestPalindromeSubseq(self, s: str) -> int:
a = s
b = a[::-1]
t = []
for i in range(len(a)+1):
l = []
for j in range(len(b) + 1):
l.append(0)
t.append(l)
for i in range(1, len(a) +1, 1):
for j in range(1, len(b) +1, 1):
if a[i-1] == b[j-1]:
t[i][j] = 1+ t[i-1][j-1]
else:
t[i][j] = max(t[i-1][j], t[i][j-1])
return t[len(a)][len(b)]
Ali and Helping innocent people | Book of Potion making |
Duration | Birthday Party |
e-maze-in | Bricks Game |
Char Sum | Two Strings |
Anagrams | Prime Number |
Lexical Sorting Reloaded | 1514A - Perfectly Imperfect Array |
580A- Kefa and First Steps | 1472B- Fair Division |
996A - Hit the Lottery | MSNSADM1 Football |
MATCHES Playing with Matches | HRDSEQ Hard Sequence |
DRCHEF Doctor Chef | 559. Maximum Depth of N-ary Tree |
821. Shortest Distance to a Character | 1441. Build an Array With Stack Operations |
1356. Sort Integers by The Number of 1 Bits | 922. Sort Array By Parity II |
344. Reverse String | 1047. Remove All Adjacent Duplicates In String |
977. Squares of a Sorted Array | 852. Peak Index in a Mountain Array |
461. Hamming Distance | 1748. Sum of Unique Elements |